What is (\partial)/(\partial y)(x^2+yz) ?

The answer to (\partial)/(\partial y)(x^2+yz) is z

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(\partial)/(\partial y)(x^2+yz)

\frac{\partial}{\partial y} (x^{2} + yz)

z

Solution steps

\frac{\partial}{\partial y} (x^{2} + yz)

Treat

x, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x^{2}) + \frac{\partial}{\partial y} (yz)

\frac{\partial}{\partial y} (x^{2}) = 0

\frac{\partial}{\partial y} (yz) = z

= 0 + z

Simplify

= z

\frac{d}{d x} (ln (h + \frac{1}{2 a x ^{2}} + b))

x \to 0 lim (\frac{1 - cos ( 5 x )}{sin ( 3 x )})

3 \frac{d r}{d s} = e^{r - 2 s}

(x, y) \to (4, 2) lim (6 x + 3 y)

f (x) = e^{2 x} - 6 e^{x} + 3

What is (\partial)/(\partial y)(x^2+yz) ?
The answer to (\partial)/(\partial y)(x^2+yz) is z