What is (\partial)/(\partial x)(-t+x) ?

The answer to (\partial)/(\partial x)(-t+x) is 1

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(\partial)/(\partial x)(-t+x)

\frac{\partial}{\partial x} (- t + x)

1

Solution steps

\frac{\partial}{\partial x} (- t + x)

Treat

t

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{\partial}{\partial x} (t) + \frac{\partial}{\partial x} (x)

\frac{\partial}{\partial x} (t) = 0

\frac{\partial}{\partial x} (x) = 1

= - 0 + 1

Simplify

= 1

\int_{- \frac{π}{3}}^{\frac{π}{3}} 1

x^{\frac{5}{8}}

x \to - 1 lim ((x + 2 x^{4})^{5})

t y^{^{'}} = 2 y - 3 t^{3} cos (4 t)

\int \frac{5}{2 + 5 x} d x

What is (\partial)/(\partial x)(-t+x) ?
The answer to (\partial)/(\partial x)(-t+x) is 1