What is (\partial)/(\partial y)(e^{x^4}-y) ?

The answer to (\partial)/(\partial y)(e^{x^4}-y) is -1

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(\partial)/(\partial y)(e^{x^4}-y)

\frac{\partial}{\partial y} (e^{x^{4}} - y)

- 1

Solution steps

\frac{\partial}{\partial y} (e^{x^{4}} - y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (e^{x^{4}}) - \frac{\partial}{\partial y} (y)

\frac{\partial}{\partial y} (e^{x^{4}}) = 0

\frac{\partial}{\partial y} (y) = 1

= 0 - 1

Simplify

= - 1

\frac{d}{d x} ((sin (5 x))^{2})

\frac{d}{d x} (\frac{1}{x ln ( x )})

x \to 0 - lim (1 + x e^{x})

x \to - 1 lim (\frac{3 x}{x ^{2} + 1})

\frac{\partial}{\partial x} (6 x y - 6 x)

What is (\partial)/(\partial y)(e^{x^4}-y) ?
The answer to (\partial)/(\partial y)(e^{x^4}-y) is -1