What is the derivative of-x^2-4x+4 ?

The derivative of-x^2-4x+4 is -2x-4

What is the first derivative of-x^2-4x+4 ?

The first derivative of-x^2-4x+4 is -2x-4

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\frac{d}{d x} (- x^{2} - 4 x + 4)

- 2 x - 4

Solution steps

\frac{d}{d x} (- x^{2} - 4 x + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (x^{2}) - \frac{d}{d x} (4 x) + \frac{d}{d x} (4)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (4) = 0

= - 2 x - 4 + 0

Simplify

= - 2 x - 4

x^{2} y^{^{''}} - 3 x y^{^{'}} - 2 y = 0

x \to - \frac{π}{3} lim (- sec (x))

\int (x (x + 1)^{3}) d x

(3 x^{4} - x + 1) (- x^{5} + 4)

\int \frac{x - 1}{x ^{2} ( x + 1 )} d x

What is the derivative of-x^2-4x+4 ?
The derivative of-x^2-4x+4 is -2x-4
What is the first derivative of-x^2-4x+4 ?
The first derivative of-x^2-4x+4 is -2x-4