What is the tangent of f(x)=x+sqrt(x),(4,6) ?

The tangent of f(x)=x+sqrt(x),(4,6) is y= 5/4 x+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=x+sqrt(x),(4,6)

tangent of

f (x) = x + x, (4, 6)

y = \frac{5}{4} x + 1

Solution steps

Find the slope of

f (x) = x + x : \frac{df ( x )}{d x} = 1 + \frac{1}{2 x}

Compute the slope of

f (x) = x + x

(4, 6) : m = \frac{5}{4}

Find the line with slope m=

\frac{5}{4}

and passing through

(4, 6) : y = \frac{5}{4} x + 1

y = \frac{5}{4} x + 1

\int \frac{1}{( 144 - x ^{2} ) ^{\frac{3}{2}}} d x

\frac{d}{d x} (e^{- x - y})

\int y^{2} cos (x) + cos (y) d x

\int \frac{x ^{3}}{( x - 1 ) ( x ^{2} + 3 )} d x

\frac{\partial}{\partial x} (x cos (θ))

What is the tangent of f(x)=x+sqrt(x),(4,6) ?
The tangent of f(x)=x+sqrt(x),(4,6) is y= 5/4 x+1