What is the solution for (2x+2y-3)/(-x-y-1)=(dy)/(dx) ?

The solution for (2x+2y-3)/(-x-y-1)=(dy)/(dx) is y=-x+5\W(1/(10e^{(x+c_{1))/5}})+4

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(2x+2y-3)/(-x-y-1)=(dy)/(dx)

\frac{2 x + 2 y - 3}{- x - y - 1} = \frac{d y}{d x}

y = - x + 5 W (\frac{1}{10 e ^{\frac{x + c _{1}}{5}}}) + 4

Solution steps

\frac{2 x + 2 y - 3}{- x - y - 1} = \frac{d y}{d x}

Solve using substitution:

y = - x + 5 W (\frac{1}{10 e ^{\frac{x + c _{1}}{5}}}) + 4

y = - x + 5 W (\frac{1}{10 e ^{\frac{x + c _{1}}{5}}}) + 4

x^{2} y^{^{''}} - 2 x y^{^{'}} + 2 y = x^{3} e^{x}

\int \frac{5 x}{9 x ^{2} - 4} d x

n = 0 \sum \infty e^{\frac{- n}{2}}

(x + y) d x + (x) d y = 0

\int (2 - sin (\frac{t}{4}))^{2} cos (\frac{t}{4}) d t

What is the solution for (2x+2y-3)/(-x-y-1)=(dy)/(dx) ?
The solution for (2x+2y-3)/(-x-y-1)=(dy)/(dx) is y=-x+5\W(1/(10e^{(x+c_{1))/5}})+4