What is (\partial)/(\partial y)(6xzsin(y)) ?

The answer to (\partial)/(\partial y)(6xzsin(y)) is 6xzcos(y)

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(\partial)/(\partial y)(6xzsin(y))

\frac{\partial}{\partial y} (6 x z sin (y))

6 x z cos (y)

Solution steps

\frac{\partial}{\partial y} (6 x z sin (y))

Treat

x, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 x z \frac{\partial}{\partial y} (sin (y))

Apply the common derivative:

\frac{\partial}{\partial y} (sin (y)) = cos (y)

= 6 x z cos (y)

\frac{d}{d x} (\frac{2 x}{8})

\frac{d}{d x} (- \frac{200}{x ^{2}})

\int 1 - x^{2} d x

\int (2 x - 5)^{2} d x

\frac{\partial}{\partial x} (4 x^{2} y - 4 x + 3 y^{3})

What is (\partial)/(\partial y)(6xzsin(y)) ?
The answer to (\partial)/(\partial y)(6xzsin(y)) is 6xzcos(y)