What is inverse oflaplace 3e^{-s} ?

The answer to inverse oflaplace 3e^{-s} is 3\delta(t-1)

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inverse oflaplace 3e^{-s}

inverse laplace

3 e^{- s}

3 δ (t - 1)

Solution steps

L^{- 1} {3 e^{- s}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= 3 L^{- 1} {e^{- s}}

L^{- 1} {e^{- s}} : δ (t - 1)

= 3 δ (t - 1)

\int_{1}^{\infty} 8 e^{- 4 x} d x

y = cot^{2} (5 x)

f (x) = \frac{4}{x ^{3}}

(x^{11} - 1)^{3}

y = 6 e^{x} cos (x)

What is inverse oflaplace 3e^{-s} ?
The answer to inverse oflaplace 3e^{-s} is 3\delta(t-1)