What is the limit as x approaches 4 of sqrt(x^2-9) ?

The limit as x approaches 4 of sqrt(x^2-9) is square root of 7

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limit as x approaches 4 of sqrt(x^2-9)

x \to 4 lim (x^{2} - 9)

7

Decimal Notation

2.64575 \dots

Solution steps

x \to 4 lim (x^{2} - 9)

Plug in the value

x = 4

= 4^{2} - 9

Simplify

= 7

2 x^{^{''}} + 6 x^{^{'}} + 9 x = 0

(2 x y + x) d x + (x^{2} + y) d y = 0

\int 9.8 x d x

\frac{\partial}{\partial t} (0)

\int - 4 x^{\frac{3}{2}} + 3 x^{\frac{2}{3}} - 4 x^{2} d x

What is the limit as x approaches 4 of sqrt(x^2-9) ?
The limit as x approaches 4 of sqrt(x^2-9) is square root of 7