What is the integral of 1/(xsqrt(x^2+7)) ?

The integral of 1/(xsqrt(x^2+7)) is 1/(sqrt(7))ln|tan((arctan(1/(sqrt(7))x))/2)|+C

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integral of 1/(xsqrt(x^2+7))

\int \frac{1}{x x ^{2} + 7} d x

\frac{1}{7} ln tan \frac{arctan ( \frac{1}{7} x )}{2} + C

Solution steps

\int \frac{1}{x x ^{2} + 7} d x

Apply Trigonometric Substitution

: \int \frac{sec ( u )}{7 tan ( u )} d u

= \int \frac{sec ( u )}{7 tan ( u )} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{7} \cdot \int \frac{sec ( u )}{tan ( u )} d u

Apply u-substitution

: \int \frac{1}{v} d v

= \frac{1}{7} \cdot \int \frac{1}{v} d v

Use the common integral:

\int \frac{1}{v} d v = ln (∣ v ∣)

= \frac{1}{7} ln ∣ v ∣

Substitute back

= \frac{1}{7} ln tan \frac{arctan ( \frac{1}{7} x )}{2}

Add a constant to the solution

= \frac{1}{7} ln tan \frac{arctan ( \frac{1}{7} x )}{2} + C

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\frac{1}{( s + 1 ) ( s + 2 )}

x^{2} y^{^{''}} - 2 x y^{^{'}} + (2 + x^{2}) y = 0

\frac{\partial}{\partial x} (\frac{55}{( 9 + x ^{2} + y ^{2} )})

What is the integral of 1/(xsqrt(x^2+7)) ?
The integral of 1/(xsqrt(x^2+7)) is 1/(sqrt(7))ln|tan((arctan(1/(sqrt(7))x))/2)|+C