What is the derivative of e^{x^2-y^2} ?

The derivative of e^{x^2-y^2} is e^{x^2-y^2}(2x-2y(dy)/(dx))

What is the first derivative of e^{x^2-y^2} ?

The first derivative of e^{x^2-y^2} is e^{x^2-y^2}(2x-2y(dy)/(dx))

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\frac{d}{d x} (e^{x^{2} - y^{2}})

e^{x^{2} - y^{2}} (2 x - 2 y \frac{d y}{d x})

Solution steps

\frac{d}{d x} (e^{x^{2} - y^{2}})

Apply the chain rule:

e^{x^{2} - y^{2}} \frac{d}{d x} (x^{2} - y^{2})

= e^{x^{2} - y^{2}} \frac{d}{d x} (x^{2} - y^{2})

\frac{d}{d x} (x^{2} - y^{2}) = 2 x - 2 y \frac{d y}{d x}

= e^{x^{2} - y^{2}} (2 x - 2 y \frac{d y}{d x})

(- 5, - 8), (0, - 7)

\int cos (x) (7 + 7 sin^{2} (x)) d x

f (x) = 6 sin^{6} (x)

\frac{\partial}{\partial t} (t^{8} e^{- x})

e^{x} (2 x + 2)

What is the derivative of e^{x^2-y^2} ?
The derivative of e^{x^2-y^2} is e^{x^2-y^2}(2x-2y(dy)/(dx))
What is the first derivative of e^{x^2-y^2} ?
The first derivative of e^{x^2-y^2} is e^{x^2-y^2}(2x-2y(dy)/(dx))