What is the integral from 0 to 16 of 8x ?

The integral from 0 to 16 of 8x is 1024

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integral from 0 to 16 of 8x

\int_{0}^{16} 8 x d x

1024

Solution steps

\int_{0}^{16} 8 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 8 \cdot \int_{0}^{16} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{16}

= 8 [\frac{x ^{2}}{2}]_{0}^{16}

Compute the boundaries:

128

= 8 \cdot 128

Simplify

= 1024

k = 1 \sum \infty \frac{1}{1 + k ^{2}}

f (x) = x^{5} - 2 x^{3} + x - 1

\frac{d}{d x} (\frac{6 x + 2 x ^{2}}{( 3 + 2 x ) ^{2}})

\int_{- 1}^{3} x^{2} + 6 x + 3 d x

x \to 2 + lim (3 - a x - x^{2})

What is the integral from 0 to 16 of 8x ?
The integral from 0 to 16 of 8x is 1024