What is (\partial)/(\partial y)(-xsin(xy)) ?

The answer to (\partial)/(\partial y)(-xsin(xy)) is -x^2cos(xy)

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(\partial)/(\partial y)(-xsin(xy))

\frac{\partial}{\partial y} (- x sin (x y))

- x^{2} cos (x y)

Solution steps

\frac{\partial}{\partial y} (- x sin (x y))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - x \frac{\partial}{\partial y} (sin (x y))

Apply the chain rule:

cos (x y) \frac{\partial}{\partial y} (x y)

= cos (x y) \frac{\partial}{\partial y} (x y)

\frac{\partial}{\partial y} (x y) = x

= - x cos (x y) x

Simplify

- x cos (x y) x : - x^{2} cos (x y)

= - x^{2} cos (x y)

f (x) = \frac{8}{x ^{3}}

\int \frac{27}{1 - cos ( 3 x )} d x

\int (t + cos (t)) d t

\frac{d}{d y} (2 x + y)

\int \frac{1}{( arcsin ( y ) ) 1 - y ^{2}} d y

What is (\partial)/(\partial y)(-xsin(xy)) ?
The answer to (\partial)/(\partial y)(-xsin(xy)) is -x^2cos(xy)