What is the integral of 20x^3+12x^2+6 ?

The integral of 20x^3+12x^2+6 is 5x^4+4x^3+6x+C

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integral of 20x^3+12x^2+6

\int 20 x^{3} + 12 x^{2} + 6 d x

5 x^{4} + 4 x^{3} + 6 x + C

Solution steps

\int 20 x^{3} + 12 x^{2} + 6 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 20 x^{3} d x + \int 12 x^{2} d x + \int 6 d x

\int 20 x^{3} d x = 5 x^{4}

\int 12 x^{2} d x = 4 x^{3}

\int 6 d x = 6 x

= 5 x^{4} + 4 x^{3} + 6 x

Add a constant to the solution

= 5 x^{4} + 4 x^{3} + 6 x + C

\int cos^{3} (x) ln (sin (x)) d x

f (x) = \frac{3 x + 2}{3 x - 2}

\frac{d}{d x} (3 x + 2 y)

x \to 2 lim (\frac{2 - x}{x ^{2} - 4})

\frac{\partial}{\partial x} (\frac{1}{x + y ^{2}})

What is the integral of 20x^3+12x^2+6 ?
The integral of 20x^3+12x^2+6 is 5x^4+4x^3+6x+C