What is the solution for y^{(1/2)}y^'+y^{(3/2)}=1 ?

The solution for y^{(1/2)}y^'+y^{(3/2)}=1 is y=(-e^{-(3t+c_{1})/2}+1)^{2/3}

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y^{(1/2)}y^'+y^{(3/2)}=1

y^{(\frac{1}{2})} y^{^{'}} + y^{(\frac{3}{2})} = 1

y = (- e^{- \frac{3 t + c _{1}}{2}} + 1)^{\frac{2}{3}}

Solution steps

y^{(\frac{1}{2})} y^{'} (t) + y^{(\frac{3}{2})} = 1

Solve separable ODE:

y = (- e^{- \frac{3 t + c _{1}}{2}} + 1)^{\frac{2}{3}}

y = (- e^{- \frac{3 t + c _{1}}{2}} + 1)^{\frac{2}{3}}

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What is the solution for y^{(1/2)}y^'+y^{(3/2)}=1 ?
The solution for y^{(1/2)}y^'+y^{(3/2)}=1 is y=(-e^{-(3t+c_{1})/2}+1)^{2/3}