What is the solution for ((xdy-ydx))/(x^2+y^2)=0 ?

The solution for ((xdy-ydx))/(x^2+y^2)=0 is y=c_{1}x

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((xdy-ydx))/(x^2+y^2)=0

\frac{( x d y - y d x )}{x ^{2} + y ^{2}} = 0

y = c_{1} x

Solution steps

\frac{( x d y - y d x )}{x ^{2} + y ^{2}} = 0

Solve separable ODE:

y = c_{1} x

y = c_{1} x

\int - 2 e^{8 x} d x

\frac{d}{d x} (ln^{2} (x + 3))

\frac{1}{x y}

f^{^{'}} (θ) = θ cos (θ) sin (θ)

y^{^{''}} + 8 y^{^{'}} + 32 y = 128, y (0) = 0, y^{^{'}} (0) = 0

What is the solution for ((xdy-ydx))/(x^2+y^2)=0 ?
The solution for ((xdy-ydx))/(x^2+y^2)=0 is y=c_{1}x