What is the tangent of f(x)=-2*sqrt(x),\at x=1 ?

The tangent of f(x)=-2*sqrt(x),\at x=1 is y=-x-1

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tangent of f(x)=-2*sqrt(x),\at x=1

tangent of

f (x) = - 2 \cdot x, at x = 1

y = - x - 1

Solution steps

Find the tangent point:

(1, - 2)

Find the slope of

f (x) = - 2 x : \frac{df ( x )}{d x} = - \frac{1}{x}

Compute the slope of

f (x) = - 2 x

x = 1 : m = - 1

Find the line with slope m=

- 1

and passing through

(1, - 2) : y = - x - 1

y = - x - 1

\frac{d}{d x} (\frac{6 x ^{2} + 6 x + 2}{x})

\frac{\partial}{\partial x} (cos^{4} (x^{3} y^{8}))

f (x) = arctan (x)

y = x^{4 c o s (x)}

\frac{\partial}{\partial x} (cos^{4} (x^{6} y^{5}))

What is the tangent of f(x)=-2*sqrt(x),\at x=1 ?
The tangent of f(x)=-2*sqrt(x),\at x=1 is y=-x-1