What is the sum from n=2 to infinity of (2/pi)^n ?

The sum from n=2 to infinity of (2/pi)^n is converges

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sum from n=2 to infinity of (2/pi)^n

n = 2 \sum \infty (\frac{2}{π})^{n}

converges

Solution steps

n = 2 \sum \infty (\frac{2}{π})^{n}

Apply Series Ratio Test:

converges

= converges

\frac{d}{d x} (\frac{( - 2 x + 4 ) ^{7}}{( 3 x - 5 ) ^{5}})

ln (1 + x^{3})

\frac{d x}{d t} = x^{2} e^{- 2 t}, x (0) = 3

f (x) = \frac{1}{9 x}, at x = 9

\int cos (\frac{π}{x}) d x

What is the sum from n=2 to infinity of (2/pi)^n ?
The sum from n=2 to infinity of (2/pi)^n is converges