What is (\partial)/(\partial y)(tan(xy^2)) ?

The answer to (\partial)/(\partial y)(tan(xy^2)) is sec^2(xy^2)*2xy

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(\partial)/(\partial y)(tan(xy^2))

\frac{\partial}{\partial y} (tan (x y^{2}))

sec^{2} (x y^{2}) \cdot 2 x y

Solution steps

\frac{\partial}{\partial y} (tan (x y^{2}))

Treat

x

as a constant

Apply the chain rule:

sec^{2} (x y^{2}) \frac{\partial}{\partial y} (x y^{2})

= sec^{2} (x y^{2}) \frac{\partial}{\partial y} (x y^{2})

\frac{\partial}{\partial y} (x y^{2}) = 2 x y

= sec^{2} (x y^{2}) \cdot 2 x y

\int cos^{3} (x) sin (2 x) d x

f (x) = x^{4} - 5 x^{3} + 2, at x = 2

\frac{d}{d x} (5 ln (x^{3}))

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\int x cos (mπ x) d x

What is (\partial)/(\partial y)(tan(xy^2)) ?
The answer to (\partial)/(\partial y)(tan(xy^2)) is sec^2(xy^2)*2xy