What is the tangent of 7x^2-12x+6 ?

The tangent of 7x^2-12x+6 is y=(14a_{0}-12)x-7a_{0}^2+6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of 7x^2-12x+6

tangent of

7 x^{2} - 12 x + 6

y = (14 a_{0} - 12) x - 7 a_{0}^{2} + 6

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 7 a_{0}^{2} - 12 a_{0} + 6)

Find the slope of

y = 7 x^{2} - 12 x + 6 : \frac{d y}{d x} = 14 x - 12

Compute the slope of

y = 7 x^{2} - 12 x + 6

x = a_{0} : m = 14 a_{0} - 12

Find the line with slope m=

14 a_{0} - 12

and passing through

(a_{0}, 7 a_{0}^{2} - 12 a_{0} + 6) : y = (14 a_{0} - 12) x - 7 a_{0}^{2} + 6

y = (14 a_{0} - 12) x - 7 a_{0}^{2} + 6

\int cos (\frac{x}{8}) d x

\int_{0}^{π} sec^{2} (\frac{x}{3}) d x

\frac{d y}{d x} = \frac{2 x ( y - 2 )}{x ^{2} + 1}

9 + 2 x

\int x^{2} y^{3} d x

What is the tangent of 7x^2-12x+6 ?
The tangent of 7x^2-12x+6 is y=(14a_{0}-12)x-7a_{0}^2+6