What is the sum from n=0 to infinity of 1/(0.5^n) ?

The sum from n=0 to infinity of 1/(0.5^n) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=0 to infinity of 1/(0.5^n)

n = 0 \sum \infty \frac{1}{0. 5 ^{n}}

diverges

Solution steps

n = 0 \sum \infty \frac{1}{0. 5 ^{n}}

Apply Series Geometric Test:

diverges

= diverges

(12 - 6 y + e^{- 3 x}) d x - 2 d y = 0

\int \frac{x ^{3}}{x ^{4} + 10} d x

(sin^{3} (t))^{^{'}}

y^{^{''}} = - 4 y + e^{x}

\int \frac{x ^{2} - 3 x - 8}{x ^{2} - 2 x + 1} d x

What is the sum from n=0 to infinity of 1/(0.5^n) ?
The sum from n=0 to infinity of 1/(0.5^n) is diverges