What is the derivative of x(x+4^2) ?

The derivative of x(x+4^2) is 3x^2+16x+16

What is the first derivative of x(x+4^2) ?

The first derivative of x(x+4^2) is 3x^2+16x+16

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (x (x + 4)^{2})

3 x^{2} + 16 x + 16

Solution steps

\frac{d}{d x} (x (x + 4)^{2})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = (x + 4)^{2}

= \frac{d x}{d x} (x + 4)^{2} + \frac{d}{d x} ((x + 4)^{2}) x

\frac{d x}{d x} = 1

\frac{d}{d x} ((x + 4)^{2}) = 2 (x + 4)

= 1 \cdot (x + 4)^{2} + 2 (x + 4) x

Simplify

1 \cdot (x + 4)^{2} + 2 (x + 4) x : 3 x^{2} + 16 x + 16

= 3 x^{2} + 16 x + 16

\frac{\partial}{\partial x} (10 x^{2} y + 5 x y^{3})

\frac{d}{d x} ((ln (x))^{8})

y^{^{''}} + 4 y^{^{'}} + 4 y = \frac{( e ^{2 x} )}{( x )}

\frac{A}{y ^{8}} + B e^{y}

\int \frac{x - 5}{x} d x

What is the derivative of x(x+4^2) ?
The derivative of x(x+4^2) is 3x^2+16x+16
What is the first derivative of x(x+4^2) ?
The first derivative of x(x+4^2) is 3x^2+16x+16