What is the integral of sin(4)(x) ?

The integral of sin(4)(x) is 1/2 sin(4)x^2+C

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integral of sin(4)(x)

\int sin (4) (x) d x

\frac{1}{2} sin (4) x^{2} + C

Solution steps

\int sin (4) x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= sin (4) \cdot \int x d x

Apply the Power Rule

: \frac{x ^{2}}{2}

= sin (4) \frac{x ^{2}}{2}

Simplify

sin (4) \frac{x ^{2}}{2} : \frac{1}{2} sin (4) x^{2}

= \frac{1}{2} sin (4) x^{2}

Add a constant to the solution

= \frac{1}{2} sin (4) x^{2} + C

e^{1 - x}

\int \frac{1 + t + t ^{2}}{t} d t

h \to 0 lim (\frac{h}{h})

\frac{x ^{4}}{6} - 10 x

\frac{d}{d x} (\frac{c ^{2} - x ^{2}}{c ^{2} + x ^{2}})

What is the integral of sin(4)(x) ?
The integral of sin(4)(x) is 1/2 sin(4)x^2+C