What is laplacetransform sin(x-5) ?

The answer to laplacetransform sin(x-5) is (-sin(5)s+cos(5))/(s^2+1)

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laplacetransform sin(x-5)

laplace transform

sin (x - 5)

\frac{- sin ( 5 ) s + cos ( 5 )}{s ^{2} + 1}

Solution steps

L {sin (x - 5)}

Use Laplace Transform table:

L {sin (a t + b)} = \frac{s \cdot sin ( b ) + a \cdot cos ( b )}{s ^{2} + a ^{2}}

L {sin (x - 5)} = \frac{s sin ( - 5 ) + 1 \cdot cos ( - 5 )}{s ^{2} + 1 ^{2}}

= \frac{s sin ( - 5 ) + 1 \cdot cos ( - 5 )}{s ^{2} + 1 ^{2}}

= \frac{- sin ( 5 ) s + cos ( 5 )}{s ^{2} + 1}

n = 1 \sum \infty \frac{3}{n ln ( 9 n )}

f (x) = (x + (x + sin^{2} (x))^{3})^{4}

\int x^{2} cos (21 x) d x

\int_{0}^{5} ∣ 3 - x ∣ d x

\frac{\partial}{\partial x} (y \cdot r^{2})

What is laplacetransform sin(x-5) ?
The answer to laplacetransform sin(x-5) is (-sin(5)s+cos(5))/(s^2+1)