What is the integral from 0 to pi/4 of 9sec(x) ?

The integral from 0 to pi/4 of 9sec(x) is 9ln(1+sqrt(2))

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integral from 0 to pi/4 of 9sec(x)

\int_{0}^{\frac{π}{4}} 9 sec (x) d x

9 ln (1 + 2)

Decimal Notation

7.93236 \dots

Solution steps

\int_{0}^{\frac{π}{4}} 9 sec (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 \cdot \int_{0}^{\frac{π}{4}} sec (x) d x

Use the common integral:

\int sec (x) d x = ln ∣ tan (x) + sec (x) ∣

= 9 [ln ∣ tan (x) + sec (x) ∣]_{0}^{\frac{π}{4}}

Compute the boundaries:

ln (1 + 2)

= 9 ln (1 + 2)

\frac{d y}{d x} = (x + y + 1)^{2} - (x + y - 1)^{2}

\int \frac{x - 3}{( x ^{2} + 2 x + 4 ) ^{2}} d x

\int_{0}^{21} x 21 - x d x

\int (e^{x} - 5)^{2} d x

\frac{\partial}{\partial x} (x y + z^{2})

What is the integral from 0 to pi/4 of 9sec(x) ?
The integral from 0 to pi/4 of 9sec(x) is 9ln(1+sqrt(2))