What is the integral of-1/(2sqrt(x)) ?

The integral of-1/(2sqrt(x)) is -sqrt(x)+C

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integral of-1/(2sqrt(x))

\int - \frac{1}{2 x} d x

- x + C

Solution steps

\int - \frac{1}{2 x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{2} \cdot \int \frac{1}{x} d x

Apply the Power Rule

: 2 x^{\frac{1}{2}}

= - \frac{1}{2} \cdot 2 x^{\frac{1}{2}}

Simplify

- \frac{1}{2} \cdot 2 x^{\frac{1}{2}} : - x

= - x

Add a constant to the solution

= - x + C

\frac{6 x}{4 - x ^{2}}, at x = 0

\frac{d}{d x} (4 7 x^{2} + 9)

\int \frac{x}{x ^{2} + 4} d x

5 x (x^{3} - 5 x + 5)

\frac{\partial}{\partial x} (4 ln (\frac{2 x y}{7 z}))

What is the integral of-1/(2sqrt(x)) ?
The integral of-1/(2sqrt(x)) is -sqrt(x)+C