What is the integral of xe^{1-x} ?

The integral of xe^{1-x} is -e^{1-x}x-e^{1-x}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of xe^{1-x}

\int x e^{1 - x} d x

- e^{1 - x} x - e^{1 - x} + C

Solution steps

\int x e^{1 - x} d x

Apply Integration By Parts

: - e^{1 - x} x - \int - e^{1 - x} d x

= - e^{1 - x} x - \int - e^{1 - x} d x

\int - e^{1 - x} d x = e^{1 - x}

= - e^{1 - x} x - e^{1 - x}

Add a constant to the solution

= - e^{1 - x} x - e^{1 - x} + C

f (x) = x sin (\frac{1}{x})

y = x^{2} - 3 x - 2, (2, - 4)

x = 2 - y^{2}, x = y^{4}

x \to 3 - lim (\frac{4}{x ^{2} - 9})

x^{2}, 2 - x

What is the integral of xe^{1-x} ?
The integral of xe^{1-x} is -e^{1-x}x-e^{1-x}+C