What is the derivative of (2x^2)/(3y^2) ?

The derivative of (2x^2)/(3y^2) is (4x)/(3y^2)

What is the first derivative of (2x^2)/(3y^2) ?

The first derivative of (2x^2)/(3y^2) is (4x)/(3y^2)

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derivative of

\frac{2 x ^{2}}{3 y ^{2}}

\frac{4 x}{3 y ^{2}}

Solution steps

\frac{d}{d x} (\frac{2 x ^{2}}{3 y ^{2}})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{2}{3 y ^{2}} \frac{d}{d x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{2}{3 y ^{2}} \cdot 2 x^{2 - 1}

Simplify

\frac{2}{3 y ^{2}} \cdot 2 x^{2 - 1} : \frac{4 x}{3 y ^{2}}

= \frac{4 x}{3 y ^{2}}

y^{^{'}} + \frac{y}{x} = 4 x^{2}

\frac{d y}{d x} = \frac{e ^{x}}{5 + e ^{x}}

\int \frac{( ln ( z ) ) ^{3}}{z} d z

x \to 0 lim (\frac{1}{4 x} - \frac{1}{( e ^{4 x} - 1 )})

\int \frac{1}{x ^{\frac{11}{5}}} d x

What is the derivative of (2x^2)/(3y^2) ?
The derivative of (2x^2)/(3y^2) is (4x)/(3y^2)
What is the first derivative of (2x^2)/(3y^2) ?
The first derivative of (2x^2)/(3y^2) is (4x)/(3y^2)