What is (\partial)/(\partial x)(3xz+y^2) ?

The answer to (\partial)/(\partial x)(3xz+y^2) is 3z

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(\partial)/(\partial x)(3xz+y^2)

\frac{\partial}{\partial x} (3 x z + y^{2})

3 z

Solution steps

\frac{\partial}{\partial x} (3 x z + y^{2})

Treat

z, y

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 x z) + \frac{\partial}{\partial x} (y^{2})

\frac{\partial}{\partial x} (3 x z) = 3 z

\frac{\partial}{\partial x} (y^{2}) = 0

= 3 z + 0

Simplify

= 3 z

\int_{1}^{16} \frac{1}{9 - x} d x

f (x) = tan (3 x), at x = \frac{π}{9}

\int 2 + 2 cos (4 x) d x

\frac{\partial}{\partial y} (\frac{x}{( x ^{2} + y ^{2} )})

\frac{d}{d x} (sin (\frac{2 x}{x ^{4} - 4 x}))

What is (\partial)/(\partial x)(3xz+y^2) ?
The answer to (\partial)/(\partial x)(3xz+y^2) is 3z