What is the first derivative of 2x^2+5 ?

The first derivative of 2x^2+5 is 4x

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derivative of 2x^2+5

\frac{d}{d x} (2 x^{2} + 5)

4 x

Solution steps

\frac{d}{d x} (2 x^{2} + 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (5)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (5) = 0

= 4 x + 0

Simplify

= 4 x

y = cot^{2} (cos (x))

\frac{d}{d t} (\frac{t}{t - 2})

\int \frac{- 1 - u}{u ^{3} + u ^{2} - 8 u - 12} d u

\int 2 x^{2} + 3 d x

\frac{d}{d x} (- \frac{13}{x ^{4}})