What is the integral of (-2)/(z^3) ?

The integral of (-2)/(z^3) is 1/(z^2)+C

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integral of (-2)/(z^3)

\int \frac{- 2}{z ^{3}} d z

\frac{1}{z ^{2}} + C

Solution steps

\int \frac{- 2}{z ^{3}} d z

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 2 \cdot \int \frac{1}{z ^{3}} d z

Apply the Power Rule

: - \frac{1}{2 z ^{2}}

= - 2 (- \frac{1}{2 z ^{2}})

Simplify

- 2 (- \frac{1}{2 z ^{2}}) : \frac{1}{z ^{2}}

= \frac{1}{z ^{2}}

Add a constant to the solution

= \frac{1}{z ^{2}} + C

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