What is the derivative of 2sin^2(t) ?

The derivative of 2sin^2(t) is 2sin(2t)

What is the first derivative of 2sin^2(t) ?

The first derivative of 2sin^2(t) is 2sin(2t)

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derivative of

2 sin^{2} (t)

2 sin (2 t)

Solution steps

\frac{d}{d t} (2 sin^{2} (t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d t} (sin^{2} (t))

Apply the chain rule:

2 sin (t) \frac{d}{d t} (sin (t))

= 2 sin (t) \frac{d}{d t} (sin (t))

\frac{d}{d t} (sin (t)) = cos (t)

= 2 \cdot 2 sin (t) cos (t)

Simplify

2 \cdot 2 sin (t) cos (t) : 2 sin (2 t)

= 2 sin (2 t)

f (x) = \frac{x}{e ^{x} - 1}

\int_{9}^{16} \frac{1}{8 - x} d x

y = x, y = (x - 1)^{2}

\int \frac{( ln ( x ) ) ^{42}}{x} d x

\int \frac{( 9 + x + x )}{x} d x

What is the derivative of 2sin^2(t) ?
The derivative of 2sin^2(t) is 2sin(2t)
What is the first derivative of 2sin^2(t) ?
The first derivative of 2sin^2(t) is 2sin(2t)