What is the d/(dt)(e^t+e^{-t}+t) ?

The d/(dt)(e^t+e^{-t}+t) is e^t-e^{-t}+1

What is the first d/(dt)(e^t+e^{-t}+t) ?

The first d/(dt)(e^t+e^{-t}+t) is e^t-e^{-t}+1

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\frac{d}{d t} (e^{t} + e^{- t} + t)

e^{t} - e^{- t} + 1

Solution steps

\frac{d}{d t} (e^{t} + e^{- t} + t)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (e^{t}) + \frac{d}{d t} (e^{- t}) + \frac{d t}{d t}

\frac{d}{d t} (e^{t}) = e^{t}

\frac{d}{d t} (e^{- t}) = - e^{- t}

\frac{d t}{d t} = 1

= e^{t} - e^{- t} + 1

\int \frac{7}{θ ^{2}} cos (\frac{7}{θ}) d θ

\frac{\partial}{\partial x} (1 - \frac{1}{x})

\frac{1}{8 x}

y = x, (25, 5)

f (x) = x + \frac{7}{x}

What is the d/(dt)(e^t+e^{-t}+t) ?
The d/(dt)(e^t+e^{-t}+t) is e^t-e^{-t}+1
What is the first d/(dt)(e^t+e^{-t}+t) ?
The first d/(dt)(e^t+e^{-t}+t) is e^t-e^{-t}+1