What is the derivative of x^2-y^2 ?

The derivative of x^2-y^2 is 2x-2y(dy)/(dx)

What is the first derivative of x^2-y^2 ?

The first derivative of x^2-y^2 is 2x-2y(dy)/(dx)

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\frac{d}{d x} (x^{2} - y^{2})

2 x - 2 y \frac{d y}{d x}

Solution steps

\frac{d}{d x} (x^{2} - y^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (y^{2})

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (y^{2}) = 2 y \frac{d y}{d x}

= 2 x - 2 y \frac{d y}{d x}

\int cos^{2} (wt) d t

x \to - 3 lim (\frac{x}{x} + \frac{1}{3})

\frac{d}{d x} (x ln ∣ cos (x) ∣)

\int \frac{sin ( 8 x )}{8} d x

\int \frac{13}{( 1 - x ^{2} ) ^{\frac{3}{2}}} d x

What is the derivative of x^2-y^2 ?
The derivative of x^2-y^2 is 2x-2y(dy)/(dx)
What is the first derivative of x^2-y^2 ?
The first derivative of x^2-y^2 is 2x-2y(dy)/(dx)