What is the sum from n=1 to infinity of (2n)/(5n+1) ?

The sum from n=1 to infinity of (2n)/(5n+1) is diverges

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sum from n=1 to infinity of (2n)/(5n+1)

n = 1 \sum \infty \frac{2 n}{5 n + 1}

diverges

Solution steps

n = 1 \sum \infty \frac{2 n}{5 n + 1}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 2 \cdot n = 1 \sum \infty \frac{n}{5 n + 1}

Apply Series Divergence Test:

diverges

= 2 diverges

= diverges

\frac{\partial}{\partial y} (\frac{12 x}{x + y})

\frac{d y}{d x} = y - 2

sin (3 x + 1)

x \to - 7 lim (- 13)

s (t) = \frac{1}{t + 1}

What is the sum from n=1 to infinity of (2n)/(5n+1) ?
The sum from n=1 to infinity of (2n)/(5n+1) is diverges