What is the solution for (dy)/(dx)+3y=x^2 ?

The solution for (dy)/(dx)+3y=x^2 is y=(x^2)/3-(2(3x-1))/(27)+(c_{1})/(e^{3x)}

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(dy)/(dx)+3y=x^2

\frac{d y}{d x} + 3 y = x^{2}

y = \frac{x ^{2}}{3} - \frac{2 ( 3 x - 1 )}{27} + \frac{c _{1}}{e ^{3 x}}

Solution steps

\frac{d y}{d x} + 3 y = x^{2}

Solve linear ODE:

y = \frac{x ^{2}}{3} - \frac{2 ( 3 x - 1 )}{27} + \frac{c _{1}}{e ^{3 x}}

y = \frac{x ^{2}}{3} - \frac{2 ( 3 x - 1 )}{27} + \frac{c _{1}}{e ^{3 x}}

\int \frac{tan ^{3} ( θ )}{cos ^{2} ( θ )} d θ

f (x) = x^{2} - 3 x + 2, at x = 1

(x + 9) (9 x + 7)

\int x 7 - x^{2} d x

\frac{\partial}{\partial x} (\frac{2 x + y}{( x + 2 y ) ^{2}})

What is the solution for (dy)/(dx)+3y=x^2 ?
The solution for (dy)/(dx)+3y=x^2 is y=(x^2)/3-(2(3x-1))/(27)+(c_{1})/(e^{3x)}