What is the derivative of (2e^x-x^5/(1-3x^5)) ?

The derivative of (2e^x-x^5/(1-3x^5)) is (-6e^xx^5-5x^4+30e^xx^4+2e^x)/((1-3x^5)^2)

What is the first derivative of (2e^x-x^5/(1-3x^5)) ?

The first derivative of (2e^x-x^5/(1-3x^5)) is (-6e^xx^5-5x^4+30e^xx^4+2e^x)/((1-3x^5)^2)

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\frac{d}{d x} (\frac{2 e ^{x} - x ^{5}}{1 - 3 x ^{5}})

\frac{- 6 e ^{x} x ^{5} - 5 x ^{4} + 30 e ^{x} x ^{4} + 2 e ^{x}}{( 1 - 3 x ^{5} ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{2 e ^{x} - x ^{5}}{1 - 3 x ^{5}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 2 e ^{x} - x ^{5} ) ( 1 - 3 x ^{5} ) - \frac{d}{d x} ( 1 - 3 x ^{5} ) ( 2 e ^{x} - x ^{5} )}{( 1 - 3 x ^{5} ) ^{2}}

\frac{d}{d x} (2 e^{x} - x^{5}) = 2 e^{x} - 5 x^{4}

\frac{d}{d x} (1 - 3 x^{5}) = - 15 x^{4}

= \frac{( 2 e ^{x} - 5 x ^{4} ) ( 1 - 3 x ^{5} ) - ( - 15 x ^{4} ) ( 2 e ^{x} - x ^{5} )}{( 1 - 3 x ^{5} ) ^{2}}

Simplify

\frac{( 2 e ^{x} - 5 x ^{4} ) ( 1 - 3 x ^{5} ) - ( - 15 x ^{4} ) ( 2 e ^{x} - x ^{5} )}{( 1 - 3 x ^{5} ) ^{2}} : \frac{- 6 e ^{x} x ^{5} - 5 x ^{4} + 30 e ^{x} x ^{4} + 2 e ^{x}}{( 1 - 3 x ^{5} ) ^{2}}

= \frac{- 6 e ^{x} x ^{5} - 5 x ^{4} + 30 e ^{x} x ^{4} + 2 e ^{x}}{( 1 - 3 x ^{5} ) ^{2}}

\frac{d}{d x} (x e^{x y + 1})

f (x) = x^{2} - 3 x + 2, at x = 2

\int \frac{2 x - 3}{6} d x

ln (x^{2})

\frac{1}{( s + 3 )}

What is the derivative of (2e^x-x^5/(1-3x^5)) ?
The derivative of (2e^x-x^5/(1-3x^5)) is (-6e^xx^5-5x^4+30e^xx^4+2e^x)/((1-3x^5)^2)
What is the first derivative of (2e^x-x^5/(1-3x^5)) ?
The first derivative of (2e^x-x^5/(1-3x^5)) is (-6e^xx^5-5x^4+30e^xx^4+2e^x)/((1-3x^5)^2)