What is the solution for y^{''}-11y^'+24y=e^{-4t} ?

The solution for y^{''}-11y^'+24y=e^{-4t} is y=c_{1}e^{8t}+c_{2}e^{3t}+1/84 e^{-4t}

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y^{''}-11y^'+24y=e^{-4t}

y^{^{''}} - 11 y^{^{'}} + 24 y = e^{- 4 t}

y = c_{1} e^{8 t} + c_{2} e^{3 t} + \frac{1}{84} e^{- 4 t}

Solution steps

y^{''} (t) - 11 y^{'} (t) + 24 y = e^{- 4 t}

Solve linear ODE:

y = c_{1} e^{8 t} + c_{2} e^{3 t} + \frac{1}{84} e^{- 4 t}

y = c_{1} e^{8 t} + c_{2} e^{3 t} + \frac{1}{84} e^{- 4 t}

\frac{d}{d x} ((4 x - 3)^{\frac{1}{3}})

\frac{\partial}{\partial x} (\frac{1}{( 1 + x ) ^{2}})

\frac{d}{d x} (\frac{x ∣ x ∣}{2})

\frac{60}{x}

\int \frac{1}{9 - x ^{2}} d x

What is the solution for y^{''}-11y^'+24y=e^{-4t} ?
The solution for y^{''}-11y^'+24y=e^{-4t} is y=c_{1}e^{8t}+c_{2}e^{3t}+1/84 e^{-4t}