What is the integral of (3/(x^5)) ?

The integral of (3/(x^5)) is -3/(4x^4)+C

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integral of (3/(x^5))

\int (\frac{3}{x ^{5}}) d x

- \frac{3}{4 x ^{4}} + C

Solution steps

\int \frac{3}{x ^{5}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int \frac{1}{x ^{5}} d x

Apply the Power Rule

: - \frac{1}{4 x ^{4}}

= 3 (- \frac{1}{4 x ^{4}})

Simplify

3 (- \frac{1}{4 x ^{4}}) : - \frac{3}{4 x ^{4}}

= - \frac{3}{4 x ^{4}}

Add a constant to the solution

= - \frac{3}{4 x ^{4}} + C

\frac{d}{d x} (e^{- 7 x} cos (7 x))

y = 2 x^{2} + 5, (- 1, 7)

f (x) = x^{2} e^{x} - 2 x e^{x} + 2 e^{x}

\int tan^{4} (5 t) d t

\int \frac{1 + 3 x}{( 1 - x ) ( 3 x - 5 )} d x