What is the tangent of y=x^2-x+7 ?

The tangent of y=x^2-x+7 is y=(2a_{0}-1)x-a_{0}^2+7

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tangent of y=x^2-x+7

tangent of

y = x^{2} - x + 7

y = (2 a_{0} - 1) x - a_{0}^{2} + 7

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, a_{0}^{2} - a_{0} + 7)

Find the slope of

y = x^{2} - x + 7 : \frac{d y}{d x} = 2 x - 1

Compute the slope of

y = x^{2} - x + 7

x = a_{0} : m = 2 a_{0} - 1

Find the line with slope m=

2 a_{0} - 1

and passing through

(a_{0}, a_{0}^{2} - a_{0} + 7) : y = (2 a_{0} - 1) x - a_{0}^{2} + 7

y = (2 a_{0} - 1) x - a_{0}^{2} + 7

\frac{d x}{d t} = 3 x t^{2} - 3 t^{2}

\int_{0}^{l n (5)} e^{x} - e^{- 3 x} d x

\frac{x}{4 x + 6}

\frac{\partial}{\partial x} (x y + \frac{4}{x} + \frac{2}{y})

y = ln (2) (x + 3)

What is the tangent of y=x^2-x+7 ?
The tangent of y=x^2-x+7 is y=(2a_{0}-1)x-a_{0}^2+7