What is the integral from 0 to 9 of 2sqrt(x)-(2x)/3 ?

The integral from 0 to 9 of 2sqrt(x)-(2x)/3 is 9

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integral from 0 to 9 of 2sqrt(x)-(2x)/3

\int_{0}^{9} 2 x - \frac{2 x}{3} d x

9

Solution steps

\int_{0}^{9} 2 x - \frac{2 x}{3} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{9} 2 x d x - \int_{0}^{9} \frac{2 x}{3} d x

\int_{0}^{9} 2 x d x = 36

\int_{0}^{9} \frac{2 x}{3} d x = 27

= 36 - 27

Simplify

= 9

S (t) = \frac{60 t ^{2}}{t ^{2} + 150}

x x^{2} + 60 (2.9)

f (x) = e^{10 x}

r = 3 cos (3 θ)

\frac{\partial}{\partial y} (x^{2} y^{2} e^{2 x y})

What is the integral from 0 to 9 of 2sqrt(x)-(2x)/3 ?
The integral from 0 to 9 of 2sqrt(x)-(2x)/3 is 9