What is (\partial)/(\partial y)(x/((y+z))) ?

The answer to (\partial)/(\partial y)(x/((y+z))) is -x/((y+z)^2)

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(\partial)/(\partial y)(x/((y+z)))

\frac{\partial}{\partial y} (\frac{x}{( y + z )})

- \frac{x}{( y + z ) ^{2}}

Solution steps

\frac{\partial}{\partial y} (\frac{x}{( y + z )})

Treat

x, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x \frac{\partial}{\partial y} (\frac{1}{y + z})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= x \frac{\partial}{\partial y} ((y + z)^{- 1})

Apply the chain rule:

- \frac{1}{( y + z ) ^{2}} \frac{\partial}{\partial y} (y + z)

= - \frac{1}{( y + z ) ^{2}} \frac{\partial}{\partial y} (y + z)

\frac{\partial}{\partial y} (y + z) = 1

= x (- \frac{1}{( y + z ) ^{2}} \cdot 1)

Simplify

x (- \frac{1}{( y + z ) ^{2}} \cdot 1) : - \frac{x}{( y + z ) ^{2}}

= - \frac{x}{( y + z ) ^{2}}

\frac{\partial}{\partial x} (x ln (x))

\frac{d}{d x} (2 x + \frac{200}{x})

f (x) = \frac{32}{0}

\frac{d}{d x} (ln^{2} (x) + 2 ln (x))

\int \frac{1}{x ^{2} ( x ^{2} - 16 )} d x

What is (\partial)/(\partial y)(x/((y+z))) ?
The answer to (\partial)/(\partial y)(x/((y+z))) is -x/((y+z)^2)