What is the solution for (dy)/(dx)=(-24)/((2x+9)^3) ?

The solution for (dy)/(dx)=(-24)/((2x+9)^3) is y= 6/((2x+9)^2)+c_{1}

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(dy)/(dx)=(-24)/((2x+9)^3)

\frac{d y}{d x} = \frac{- 24}{( 2 x + 9 ) ^{3}}

y = \frac{6}{( 2 x + 9 ) ^{2}} + c_{1}

Solution steps

\frac{d y}{d x} = \frac{- 24}{( 2 x + 9 ) ^{3}}

Substitute

\frac{d y}{d x}

with

y^{'} (x)

y^{^{'}} (x) = \frac{- 24}{( 2 x + 9 ) ^{3}}

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int \frac{- 24}{( 2 x + 9 ) ^{3}} d x

\int \frac{- 24}{( 2 x + 9 ) ^{3}} d x = \frac{6}{( 2 x + 9 ) ^{2}} + c_{1}

y = \frac{6}{( 2 x + 9 ) ^{2}} + c_{1}

\frac{\partial}{\partial y} (e^{- y} cos (π x))

\int (x^{2} + e^{x} - sin (x)) d x

(3 x)^{^{'}}

\int 4 tan^{2} (x) sec^{2} (x) d x

y = 3 x, y = \frac{5}{7} x, y = 54 - x^{2}

What is the solution for (dy)/(dx)=(-24)/((2x+9)^3) ?
The solution for (dy)/(dx)=(-24)/((2x+9)^3) is y= 6/((2x+9)^2)+c_{1}