What is taylor f(x)=8.8sqrt(x) ?

The answer to taylor f(x)=8.8sqrt(x) is 8.8+4.4(x-1)-1.1(x-1)^2+0.55(x-1)^3-0.34375(x-1)^4+\ldots

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taylor f(x)=8.8sqrt(x)

taylor

f (x) = 8.8 x

8.8 + 4.4 (x - 1) - 1.1 (x - 1)^{2} + 0.55 (x - 1)^{3} - 0.34375 (x - 1)^{4} + \dots

Solution steps

Apply the Taylor Formula

= 8.8 + \frac{\frac{d}{d x} ( 8.8 x ) ( 1 )}{1 !} (x - 1) + \frac{\frac{d ^{2}}{d x ^{2}} ( 8.8 x ) ( 1 )}{2 !} (x - 1)^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( 8.8 x ) ( 1 )}{3 !} (x - 1)^{3} + \dots

Evaluate Derivatives

= 8.8 + \frac{4.4}{1 !} (x - 1) + \frac{- 2.2}{2 !} (x - 1)^{2} + \frac{3.3}{3 !} (x - 1)^{3} + \frac{- 8.25}{4 !} (x - 1)^{4} + \dots

Refine

= 8.8 + 4.4 (x - 1) - 1.1 (x - 1)^{2} + 0.55 (x - 1)^{3} - 0.34375 (x - 1)^{4} + \dots

\frac{d}{d x} (e^{2 x} x (a cos (x) + b sin (x)))

y^{^{''}} + 3 y^{^{'}} - 4 y = - 8 e^{x} cos (2 x)

\frac{d}{d x} (\frac{1}{2} x - \frac{1}{10})

\frac{\partial}{\partial u} (u^{2} + v^{2} + w^{2})

\frac{d}{d x} (e^{x} cos (x) - e^{x} sin (x))

What is taylor f(x)=8.8sqrt(x) ?
The answer to taylor f(x)=8.8sqrt(x) is 8.8+4.4(x-1)-1.1(x-1)^2+0.55(x-1)^3-0.34375(x-1)^4+\ldots