What is the derivative of 18t^2-11t+4 ?

The derivative of 18t^2-11t+4 is 36t-11

What is the first derivative of 18t^2-11t+4 ?

The first derivative of 18t^2-11t+4 is 36t-11

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derivative of

18 t^{2} - 11 t + 4

36 t - 11

Solution steps

\frac{d}{d t} (18 t^{2} - 11 t + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (18 t^{2}) - \frac{d}{d t} (11 t) + \frac{d}{d t} (4)

\frac{d}{d t} (18 t^{2}) = 36 t

\frac{d}{d t} (11 t) = 11

\frac{d}{d t} (4) = 0

= 36 t - 11 + 0

Simplify

= 36 t - 11

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\int_{5}^{8} \frac{x}{x ^{2} - 2} d x

\frac{d}{d x} (\frac{a + x ^{2}}{a - x ^{2}})

3 x ln (1 + x)

\int x^{\frac{1}{3}} + (2 x)^{\frac{1}{3}} d x

What is the derivative of 18t^2-11t+4 ?
The derivative of 18t^2-11t+4 is 36t-11
What is the first derivative of 18t^2-11t+4 ?
The first derivative of 18t^2-11t+4 is 36t-11