What is the derivative of g(t)=5(cos(pit))^2 ?

The derivative of g(t)=5(cos(pit))^2 is -10picos(pit)sin(pit)

What is the first derivative of g(t)=5(cos(pit))^2 ?

The first derivative of g(t)=5(cos(pit))^2 is -10picos(pit)sin(pit)

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derivative of

g (t) = 5 (cos (π t))^{2}

- 10 π cos (π t) sin (π t)

Solution steps

\frac{d}{d t} (5 (cos (π t))^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d t} ((cos (π t))^{2})

Apply the chain rule:

2 cos (π t) \frac{d}{d t} (cos (π t))

= 2 cos (π t) \frac{d}{d t} (cos (π t))

\frac{d}{d t} (cos (π t)) = - sin (π t) π

= 5 \cdot 2 cos (π t) (- sin (π t) π)

Simplify

= - 10 π cos (π t) sin (π t)

\int - 6 sin (3 x) d x

\frac{d}{d x} (e^{2 x} x)

(2, - 4), (6, 0)

\frac{\partial}{\partial x} (2 x cos (x^{2} + y^{2}))

x \to - 3 + lim (\frac{x ^{2} - 9}{x + 3})

What is the derivative of g(t)=5(cos(pit))^2 ?
The derivative of g(t)=5(cos(pit))^2 is -10picos(pit)sin(pit)
What is the first derivative of g(t)=5(cos(pit))^2 ?
The first derivative of g(t)=5(cos(pit))^2 is -10picos(pit)sin(pit)