What is (\partial)/(\partial x)(3x^3y^2) ?

The answer to (\partial)/(\partial x)(3x^3y^2) is 9x^2y^2

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(\partial)/(\partial x)(3x^3y^2)

\frac{\partial}{\partial x} (3 x^{3} y^{2})

9 x^{2} y^{2}

Solution steps

\frac{\partial}{\partial x} (3 x^{3} y^{2})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 y^{2} \frac{\partial}{\partial x} (x^{3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 3 y^{2} \cdot 3 x^{3 - 1}

Simplify

= 9 x^{2} y^{2}

\frac{3 x}{2 ( 1 - 2 x )}

\int cos (\frac{θ}{2}) d θ

\frac{d}{d x} (x^{2} sin (x) + 2 x cos (x) - 2 sin (x))

\int_{9}^{16} \frac{1}{9 - x} d x

\frac{d}{d x} (- \frac{11}{( x - 3 ) ^{2}})

What is (\partial)/(\partial x)(3x^3y^2) ?
The answer to (\partial)/(\partial x)(3x^3y^2) is 9x^2y^2