What is the derivative of sin(arcsin(x)+arccos(x)) ?

The derivative of sin(arcsin(x)+arccos(x)) is 0

What is the first derivative of sin(arcsin(x)+arccos(x)) ?

The first derivative of sin(arcsin(x)+arccos(x)) is 0

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derivative of

sin (arcsin (x) + arccos (x))

0

Solution steps

\frac{d}{d x} (sin (arcsin (x) + arccos (x)))

Apply the chain rule:

cos (arcsin (x) + arccos (x)) \frac{d}{d x} (arcsin (x) + arccos (x))

= cos (arcsin (x) + arccos (x)) \frac{d}{d x} (arcsin (x) + arccos (x))

\frac{d}{d x} (arcsin (x) + arccos (x)) = 0

= cos (arcsin (x) + arccos (x)) \cdot 0

Simplify

= 0

\frac{\partial}{\partial x} (2 (y - 3) (x - 2)^{3})

\int (e^{8 x} + e^{- 9 x}) d x

y = ln (3 x^{2} + 2 x - 1)

\int \frac{8 e ^{4 x}}{x} d x

y = \frac{2}{1 - x ^{2}}

What is the derivative of sin(arcsin(x)+arccos(x)) ?
The derivative of sin(arcsin(x)+arccos(x)) is 0
What is the first derivative of sin(arcsin(x)+arccos(x)) ?
The first derivative of sin(arcsin(x)+arccos(x)) is 0