What is the solution for (2xy^2+2y)dx+(2x^2y+2x)dy=0 ?

The solution for (2xy^2+2y)dx+(2x^2y+2x)dy=0 is y=(c_{1})/x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(2xy^2+2y)dx+(2x^2y+2x)dy=0

(2 x y^{2} + 2 y) d x + (2 x^{2} y + 2 x) d y = 0

y = \frac{c _{1}}{x}

Solution steps

(2 x y^{2} + 2 y) d x + (2 x^{2} y + 2 x) d y = 0

Solve separable ODE:

y = \frac{c _{1}}{x}

y = \frac{c _{1}}{x}

\frac{\partial}{\partial x} (100 e^{(- x - 2 y)})

x \to 1 lim (g (x) (f (x)))

x \to 4 lim (\frac{( 3 x ^{2} - 17 x + 20 )}{4 x ^{2} - 25 x + 36})

\int \frac{ln ( cos ( x ) )}{cos ^{2} ( x )} d x

\frac{1}{sin ( x )}

What is the solution for (2xy^2+2y)dx+(2x^2y+2x)dy=0 ?
The solution for (2xy^2+2y)dx+(2x^2y+2x)dy=0 is y=(c_{1})/x