What is area sec^2(x),8cos(x) ?

The answer to area sec^2(x),8cos(x) is 6sqrt(3)

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area sec^2(x),8cos(x)

area

sec^{2} (x), 8 cos (x)

63

Decimal Notation

10.39230 \dots

Solution steps

Apply the area formula:

\int_{- \frac{π}{3}}^{\frac{π}{3}} sec^{2} (x) - 8 cos (x) d x

Solve

\int_{- \frac{π}{3}}^{\frac{π}{3}} sec^{2} (x) - 8 cos (x) d x : 63

The area is:

= 63

x \to 3 lim (c x^{2} - 4 x)

\frac{d}{d x} (\frac{( 1 - 4 e ^{x} )}{1 - 5 cos ( x )})

x \to - 8 lim (10 x + 1)

(x^{2} + 1) \cdot \frac{d y}{d x} + 6 x (y - 1) = 0

10 y^{^{''}} - 10 y^{^{'}} + 25 y = 0